Based on detailed analysis of last 5 years' papers. Perfect for 2026 Boards prep!
| Question Example | Type/Marks | Years Repeated | Notes |
|---|---|---|---|
| A bag contains 4 red and 6 black balls. Two balls are drawn successively without replacement. Find P(both red), P(second red given first black), etc. (conditional probability). | Short Answer (2-3 marks) | 2021, 2022, 2023, 2024, 2025 | Repeated 5x; Use multiplication theorem or tree diagram; P(both red) = (4/10)×(3/9). |
| Using Bayes' theorem: A person has 3 bags with different ratios of defective/non-defective bulbs. He picks a bag at random, draws a bulb, it's defective. Find probability it came from bag X. | Long Answer (4-6 marks) | 2021 Term 2, 2022, 2023, 2024 | Repeated 4x; Tree diagram → P(bag X|defective) = [P(defective|bag X) P(bag X)] / P(defective total). |
| A random variable X has binomial distribution B(n,p). Find P(X=k), mean = np, variance = np(1-p) or probability in specific trials (e.g., 5 coins, P(exactly 3 heads)). | Short/Long Answer (3-4 marks) | 2022, 2023, 2024, 2025 | Repeated 4x; Binomial formula C(n,k) p^k (1-p)^{n-k}; mean & variance direct. |
| Assertion: If two events A and B are independent, then P(A|B) = P(A). Reason: P(A ∩ B) = P(A)P(B). | Assertion-Reason (1 mark) | 2023, 2024, 2025 | Repeated 3x; Both true, reason explains. |
| Two events A and B such that P(A) = 0.4, P(B) = 0.5, P(A∪B) = 0.7. Find P(A|B), P(A∩B), check independence. | Short Answer (2-3 marks) | 2021 Term 1, 2022, 2023, 2025 | Repeated 4x; P(A∩B) = P(A)+P(B)-P(A∪B); P(A|B) = P(A∩B)/P(B). |
| A die is thrown 6 times. Find probability of getting exactly 4 sixes or at least 2 sixes (binomial). | Short Answer (3 marks) | 2022, 2023, 2024 | Repeated 3x; n=6, p=1/6; P(X=4) = C(6,4) (1/6)^4 (5/6)^2. |
| MCQ: If P(A) = 0.3, P(B) = 0.4 and A, B independent, then P(A∩B) = ? (a) 0.12 (b) 0.7 (c) 0 (d) 1 | MCQ (1 mark) | 2021 Term 1, 2023, 2024 | Repeated 3x; Answer (a) 0.12 = 0.3 × 0.4. |
| Find mean and variance of binomial random variable with n=10, p=0.3. | Short Answer (2 marks) | 2023, 2025 | Repeated 2x; Mean = np = 3, Variance = np(1-p) = 2.1. |
| Case-based: Given medical test accuracy, prior probability of disease, apply Bayes' theorem to find posterior probability. | Case-Based (4-6 marks) | 2023, 2025 | Repeated 2x; Use tree or formula; very common real-life application. |
| Prove that if A and B are independent, then A' and B, A and B', A' and B' are also independent. | Proof (3 marks) | 2021 Term 2, 2024 | Repeated 2x; Use P(A∩B)=P(A)P(B) → show for complements. |
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